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Question 5
(3+1)(3cot 30)=tan3 602 sin 60


Solution

RHS=tan3 602 sin 60=(3)3232=333=23

LHS=(3+1)(3cot 30)=(3+1)(33).

[tan 60=3, sin 60=32 and cot 30=3]

=(3+1)(3(31))
=3(321)=3(31)=23

LHS=RHS

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