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Question

3cosec 20sec 20=


  1. 2

  2. 2sin20sin40

  3. 4

  4. 4sin20sin40


Solution

The correct option is C

4


3cosec 20sec 20=3sin 201cos 20
=3 cos20sin20sin20 cos20=2[32cos2012sin20]22sin20 cos20

=2[cos30cos20sin30sin20]22sin20 cos20
=4cos(20+30)sin40=4cos50sin40=4sin40sin40=4.

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