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Question

2+3+4+6 is equal to

A
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Solution

The correct option is A
We have cot A=cos Asin A=2 cos2 A2 sin A cos A=1+cos 2Asin 2A
Putting A=712cot 712=1+cos 15sin 15
On simplification,
We get cot 712=6+2+3+4.

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