Question

# Square root of the poynomial is √(3x+2y)2−24xy (3x−2y) (3x+2y) (2x−3y) (2x+3y)

Solution

## The correct option is A (3x−2y) √(3x+2y)2−24xy            =√9x2+4y2+12xy−24xy  =√9x2+4y2−12xy =√(3x−2y)2 =(3x−2y)

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