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Question

Square root of the poynomial is (3x+2y)224xy 
  1. (3x2y) 
  2. (3x+2y) 
  3. (2x3y) 
  4. (2x+3y) 


Solution

The correct option is A (3x2y) 
(3x+2y)224xy
           =9x2+4y2+12xy24xy
 =9x2+4y212xy
=(3x2y)2
=(3x2y)

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