Stability of ions of Ge- Sn- and P b will be in the order-A- Ge 2- Sn 4- Pb 4-C- Sn 4- Sn 2-D- Pb 2- Pb 4-

The correct options are A Ge^2+ lt; Sn^2+ lt; Pb^2+ B Ge^4+ gt; Sn^4+ gt; Pb^4+ C Sn^4+ gt; Sn^2+ D Pb^2+ gt; Pb^4+ As we go down this group (car ...

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Reactivity Towards Halogens

Stability of ...

Question

Stability of ions of $G e, S n, a n d P b$ will be in the order:

$G e^{2 +} < S n^{2 +} < P b^{2 +}$

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$G e^{4 +} > S n^{4 +} > P b^{4 +}$

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$S n^{4 +} > S n^{2 +}$

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$P b^{2 +} > P b^{4 +}$

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Solution

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Similar questions

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

P b^{4 +} + S n^{2 +} \to S n^{4 +} + P b^{2 +}

S n^{4 +} + P b^{2 +} \to P b^{4 +} + S n^{2 +}

E_{P b^{4 +} / P b^{2 +}}^{o} = 1.69 V, E_{S n^{4 +} / S n^{2 +}}^{o} = 0.15 V

{S n}^{2 +} + {2 H g}^{2 +} ⟶ {H g}_{2}^{2 +} + {S n}^{4 +}

{G e}^{2 +} + {P b}^{4 +} ⟶ {p b}^{2 +} + {G e}^{4 +}

{T 1}^{+} + {G a}^{3 +} ⟶ {G a}^{+} + {T 1}^{3 +}

It is because of the inability of $n s^{2}$ electrons of the valence shell to participate in bonding that

n s^{2}

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