Standing waves are produced in 10m long stretched string. If the string vibrates in 5 segments and wave velocity is 20m/s, then its frequency will be
A
5Hz
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B
2Hz
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C
10Hz
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D
12Hz
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Solution
The correct option is A5Hz There are 5 loops in 10 metre. Length of one loop =2m Length of two loops =2×2=4m Now, λ=4m;v=20m/sec From formula, v=vλ.⇒20=v×4⇒v=5Hz