CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

State True(1) or False(0).

The curved surface area of a frustum of a cone is πl(r1+r2) and l=h2+(r1r2)2 where, r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.

Open in App
Solution

Curved Surface area of a frustum of a cone =πl(r1+r2) where l is the slant height =h2+(r1r2)2, h is the height, r1 and r2 are the radii of the lower and upper ends of a frustum of a cone.
204658_82982_ans_9c7acd6d5e904d9bac1f2626bff62320.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combination of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon