State true or false.
A.M. of any $n$ positive numbers $a_{1}, a_{2}, a_{3}, . . . ., a_{n}$ is $A$ then $A = \frac{a_{1} + a_{2} + . . . . + a_{n}}{n}$

True

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False

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Solution

The correct option is A True
Arithmetic mean is the average of all the numbers.

Hence for n positive numbers:
$a_{1}$ , $a_{2}$ , $a_{3}$ ,.... $a_{n}$ , the arithmetic mean is $\frac{a_{1} + a_{2} + a_{3} + . . . + a_{n}}{n}$ .

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Similar questions

a_{1}, a_{2}, a_{3}, . . . . . . . . ., a_{n}

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\frac{a_{1}}{a_{2}} + \frac{a_{2}}{a_{3}} + \frac{a_{3}}{a_{4}} + . . . . . + \frac{a_{n - 1}}{a_{n}} + \frac{a_{n}}{a_{1}} > n

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If A₁, A₂, A₃,..., A_n are n numbers between a and b, such that a, A₁, A₂, A₃,..., A_n, b are in A.P., then

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