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Question

State whether the following statement is true or false.
cosAsinA+1cosA+sinA1=cosecA+cotA. (by using the identity cosec2A=1+cot2A.)

A
True
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B
False
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Solution

The correct option is A True
LHS=(cosAsinA)+1(cosA+sinA)1

taking conjugate

=(cosAsinA)+1(cosA+sinA)1×(cosA+sinA)+1(cosA+sinA)+1

multiplying we get

=cos2Asin2A+2cosA+12sinAcosA

=cos2Asin2A+2cosA+sin2A+cos2A2sinAcosA

on solving we get

=2cos2A+2cosA2sinAcosA

taking 2 common and divided, we get

=cosA+cos2AsinAcosA

we can also write in the form of

=cosAsinAcosA+cos2AsinAcosA

on solving we get

cosecA+cotA=R.H.S

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