State whether the statement is true or false.
Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

x+3

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x²+3x

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Solution

The correct option is A
x+3

$x (3 x^{2} - 27) = 3 x (x^{2} - 9) = 3 x (x + 3) (x - 3) \frac{3 x (x + 3) (x - 3)}{3 (x - 3)} = x (x + 3) = x (x + 3) = x^{2} + 3 x$

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Similar questions

Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

Divide $x (3 x^{2} - 27)$ by $3 (x - 3)$

{(3 x^{2})}^{- 3} - {(x^{9})}^{\frac{2}{3}} = \frac{1}{27}

x (3 x^{2} - 27)

3 (x - 3),

x^{2} + 3 \sqrt{3} x - 30

= (x + 5 \sqrt{3}) (x - 2 \sqrt{3})

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