Question

State whether True or False.

Divide: $-14x^6{y}^3-21x^4{y}^5+7x^5{y}^4$ by $7x^2{y}^2$, then answer is $-2x^{4}y-3x^2{y}^3+x^3{y}^2$.

• A. True
• B. False

Answer 1

The correct option is A True

$\Rightarrow -14x^6{y}^3-21x^4{y}^5+7x^5{y}^4÷7x^2{y}^2$
$\Rightarrow \frac{-14x^6{y}^3-21x^4{y}^5+7x^5{y}^4}{7x^2{y}^2}$
We take $7x^2{y}^2$common
$\Rightarrow \frac{7x^2{y}^2(-2x^{4}y-3x^2{y}^3+x^3{y}^2)}{7x^2{y}^2}$
$\Rightarrow -2x^{4}y-3x^2{y}^3+x^3{y}^2$