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Question

State whether True or False.
The H.C.F. and L.C.M. of:

a2b2b4,ab2+b3 and abb2 is b;b2(a2b2)
If true then enter 1 and if false then enter 0

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Solution

Factorizing a2b2b4,ab2+b3 and abb2,
a2b2b4=b2(a2b2)=b2(a+b)(ab)
ab2+b3=b2(a+b)
abb2=b(ab)
H.C.F. =b
L.C.M. =b2(a2b2)

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