Question

Statement 1: A $1.0$ g sample of calcium citrate $C{a}_3(C_6{H}_5{O}_7{)}_2$ (molar mass $=498$ g/mol), contains more $Ca$ than a $1.0$ g sample of calcium carbonate, $CaC{O}_3$(molar mass $=100$ g/mol)
Statement 2: There are more $Ca$ atoms in $1.0$ mol of calcium carbonate than in $1.0$ mol of calcium citrate.

• A. Both statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1
• B. Both statement 1 and statement 2 are correct and statement 2 is not the correct explanation of statement 1
• C. Statement 1 is correct but statement 2 is not correct
• D. Statement 1 is not correct but statement 2 is correct
• E. Both statement 1 and statement 2 are not correct

Answer 1

The correct option is E

Both statement 1 and statement 2 are not correct

Statement 1: A 1.0g sample of calcium citrate $C{a}_3(C_6{H}_5{O}_7{)}_2$ (molar mass $=498$ g/mol), contains $\frac{1.0g}{498g/mol}=0.002$ moles of calcium citrate.
1 mole of calcium citrate corresponds to 3 moles of Ca.
0.002 moles of calcium citrate corresponds to $3\times 0.002=0.006$ moles of Ca
1.0g sample of calcium carbonate, $CaC{O}_3$ (molar mass $=100$ g/mol) contains $\frac{1.0g}{100g/mol}=0.01$ moles of calcium carbonate
1 mole of calcium carbonate corresponds to 1 mole of $Ca$.
0.01 moles of calcium carbonate corresponds to $1\times 0.01=$0.01 moles of $Ca$
Hence, given sample of calcium citrate contains less $Ca$ than the given sample of calcium carbonate.
Statement 2: 1.0 mol of calcium carbonate $CaC{O}_3$ contains 1.0 mole of $Ca$ atoms.
1.0 mol of calcium citrate $C{a}_3(C_6{H}_5{O}_7{)}_2$ contains 3.0 moles of $C$ atoms
Hence, there are less $Ca$ atoms in 1.0 mol of calcium carbonate than in 1.0 mol of calcium citrate.
Thus, both statement 1 and statement 2 are not correct.