Question

Statement-1: Nucleophilicity order in polar-protic solvent is: $I^{-}<B{r}^{-}<C{l}^{-}<F^{-}$
Statement-2: Due to bigger size of $I^{-}$, it is less solvated in polar-protic solvent

• A. Statement-1 is true, statement-2 is true and statement-2 is the correct explanation for statement-1
• B. Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1
• C. Statement-1 is true, statement-2 is false
• D. Statement-1 is false, statement-2 is true

Answer 1

The correct option is D Statement-1 is false, statement-2 is true

In polar-protic solvent, the degree of solvation of anions increases with the decrease in the size of the anions. More the solvation, lesser is the nucleophilicity.

Therefore, the nucleophility order of halogens in polar-protic solvent is: $I^{-}>B{r}^{-}>C{l}^{-}>F^{-}$

Hence, statement-1 is false and statement-2 is true.