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Question

STATEMENT - 1: The slant height of frustum of a cone is 4 cm. and perimeters of its circular ends are 18 cm. and 6 cm. then the curved surface area is 48 sq. cm.
STATEMENT - 2: Curved surface area of frustum =π(r1+r2), where r1 and r2 are radii of the frustum and l is a slant height.

A
Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 1
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B
Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1
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C
Statement - 1 is True, Statement - 2 is False
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D
Statement - 1 is False, Statement - 2 is True
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Solution

The correct option is A Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 1
Curved surface area offrustum =π(r1+r2)l, where r1
and r2 are radii of frustum and l is a slant height
=227(9π+3π)×4=227×π(9+3)×4
=227×722(12)×4=48cm2

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