Statement A: Every monomial is a polynomial.

Statement B: Not every polynomial is a monomial.

Statement A is true, but not statement B.

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Statement B is true, but not statement A.

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Both statement A and statement B are true.

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Both statement A and statement B are false.

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Solution

The correct option is C
Both statement A and statement B are true.

An algebraic expression with only one term is called a monomial, whereas an algebraic expression with one or more(unlike) terms is called a polynomial.

Hence every monomial is a polynomial.

For example, $4 x$ is a monomial, as well as a polynomial.

Hence statement A is true.

Statement B is also true. We shall see realise this by taking an example.

Consider the polynomial $3 x^{2} + x + 3$ . Now, this polynomial has three terms. This is an example of a polynomial which is not a monomial.

In fact, one can find many such examples. Hence statement B, which is, not every polynomial is a monomial, is true.

Suggest Corrections

Similar questions

Statement 1: A polynomial P(x) of degree greater than or equal to one, when divided by x – a, leaves a remainder zero.

Statement 2: x – a is a factor of the polynomial P(x).

The polynomial x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8 when divided by (x + 1) leaves a remainder of 14 .

The value of the polynomial x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8 at x = - 1 is 14.

C O_{2}

H_{2} O

Statement 1: The polynomial $P (x) = 4 x^{3} - 3 x^{2} + 5 x - 6$ when divided by $x - 1$ gives zero as the remainder.

Statement 2: $(x - 1)$ is a factor of the polynomial $P (x) = 4 x^{3} - 3 x^{2} + 5 x - 6$ .

1

\to A = 2^i + 3^j + 6^k, \to B =^i +^j - 2^k

\to C =^i + 2^j +^k

| \to A \times (\to A \times (\to A \times \to B)) \cdot \to C | = 243

2

| \to A \times (\to A \times (\to A \times \to B)) \cdot \to C | = | \to A |^{2} | [\to A \to B \to C] |

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