Question

# Stationary waves of frequency $$300 Hz$$ are formed in a medium in which the velocity of sound is $$1200 metre/sec$$. The distance between a node and the neighbouring antinode is

A
1m
B
2m
C
3m
D
4m

Solution

## The correct option is A $$1 m$$Required distance = $$\dfrac{\lambda}{4} = \dfrac{v/n}{4} = \dfrac{1200}{4 \times 300} = 1m$$Physics

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