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Question

Stationary waves of frequency $$300 Hz$$ are formed in a medium in which the velocity of sound is $$1200 metre/sec$$. The distance between a node and the neighbouring antinode is


A
1m
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B
2m
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C
3m
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D
4m
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Solution

The correct option is A $$1 m$$
Required distance = $$\dfrac{\lambda}{4} = \dfrac{v/n}{4} = \dfrac{1200}{4 \times 300} = 1m$$

Physics

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