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Question

Stationary waves of frequency 300 Hz are formed in a string, in which the velocity of wave is 200 m/s. The distance between a node and the consecutive antinode is
  1. 16 m
  2. 2 m
  3. 32 m
  4. 4 m


Solution

The correct option is A 16 m
Given, f=300 Hz
Velocity of transverse wave is v=fλ
v=300×λ
200=300×λ
λ=23m

Distance between a node and consecutive antinode is  Δx=λ4
Δx=212=16 m.

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