Straight distance between a hotel and a railway station is $10 k m$ , but the cirular route is followed by a taxi covering $23 k m$ in $28$ minutes. What is average speed and magnitude of average velocity? Are they equal?

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Solution

(a)Total distance travelled =23km
Total time taken=28 min=28/60 hrs
Average speed;
$= \frac{T o t a l d i s t a n c e t r a v e l e l l e d}{T o t a l t i m e}$
$= \frac{23}{(\frac{28}{60})}$
$= 49.29 k m p h$
(b)Distance between hotel and station= 10km= Displacement of the taxi
Average velocity;
$= \frac{10}{(\frac{28}{60})}$
$= 21.43 k m p h$
Therefore, the two physical quantities (average speed and average velocity) are not equal.

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Straight distance between a hotel and a railway station is 10km, but the cirular route is followed by a taxi covering 23km in 28 minutes. What is average speed and magnitude of average velocity? Are they equal?

Straight distance between a hotel and a railway station is $10 k m$ , but the cirular route is followed by a taxi covering $23 k m$ in $28$ minutes. What is average speed and magnitude of average velocity? Are they equal?