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Question

Subtract 5a22a+1 from the sum of 4a2+37a and 8a7

A
9a2+3a3
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B
9a2a5
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C
9a23a+5
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D
9a2+3a5
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Solution

The correct option is D 9a2+3a5
The sum of 4a2+37a and 8a7.

4a27a+3
+8a7
__________________________________
4a2+a4
__________________________________

Now, subtracting (5a22a+1) from (4a2+a4), we get,

4a2+a4
(5a22a+1)

4a2+a4
+5a2+2a1
_______________________
9a2+3a5
_______________________

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