Question

Subtraction of $\frac{3}{4}$$-\frac{4}{5}$ is not equal to

• A. $-\frac{4}{5}+\frac{3}{4}$
• B. $-\frac{1}{20}$
• C. $\frac{4}{5}$$-\frac{3}{4}$
• D. $-\frac{4}{5}-(-\frac{3}{4})$

Answer 1

The correct option is C $\frac{4}{5}$$-\frac{3}{4}$

$\frac{3}{4}-\frac{4}{5}=\frac{15-16}{20}=-\frac{1}{20}$

$A)$ $-\frac{4}{5}+\frac{3}{4}=\frac{-16+15}{20}=-\frac{1}{20}$

$B)$ $-\frac{1}{20}$

$C)$ $\frac{4}{5}-\frac{3}{4}=\frac{16-15}{20}=\frac{1}{20}$

$D)$ $-\frac{4}{5}-(-\frac{3}{4})=\frac{-16+15}{30}=-\frac{1}{20}$

Then $\frac{4}{5}-\frac{3}{4}$ is not equel to $\frac{3}{4}-\frac{4}{5}$

Answer is $C.$