Question

Successive emission of an $\alpha$-particle and two $\beta$-particles by an atom of a radioactive element results in the formation of its:

• A. isobar
• B. isomer
• C. isotone
• D. isotope

Answer 1

The correct option is D isotope

$\alpha$-decay

${}_Z^{A}X\to {}_{Z-2}^{A-4}Y+\alpha$

$\beta$-decay

${}_Z^{A}X\to {}_{Z+1}^{A}Y+{\beta }^{-}$

Successive emission of 1$\alpha$ and 2$\beta$ particles will eventually cause no change in the atomic number of the daughter nuclei.

Hence, the daughter nuclei is an isotope of the present nuclei.