Sulphide turns orange dichromate solution into green coloured solution because of reduction of chromium ion(in dichromate solution) to __________oxidation state.

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Solution

Sulfites produce SO₂ gas, which smells of burning sulfur, when treated with dilute acid. They turn acidified K₂Cr₂O₇ from orange to green because of reduction of chromium ion(in dichromate solution) to +3 oxidation state.

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Q. _____ ion turns the orange coloured acidified potassium dichromate solution into green.

Q. When a mixture

(A)

of unknown gases is passed into the dichromate solution, then orange color turns to green; when the solution is boiled and gas passed into lime water, then lime water turns milky. Find out

(A)

Q. A salt on reaction with dil.

H_{2} S O_{4}

produces a colourless gas which turns lime water milky and an acidified orange coloured potassium dichromate solution green. The salt may be:

The chemical reaction between two substances is characterised by a change in colour from orange to green. These two substances are most likely to be :
(a) potassium dichromate solution and sulphur dioxide

(b) potassium permanganate solution and sulphur dioxide

(d) potassium dichromate solution and carbon dioxide.

Identify the anion present in the salt on the basis of the reaction given below

When dilute sulphuric acid is added to salt solution, a gas is produced which turns acidified potassium dichromate solution from orange to green.

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Sulphide turns orange dichromate solution into green coloured solution because of reduction of chromium ion(in dichromate solution) to __________oxidation state.

Sulfites produce SO2 gas, which smells of burning sulfur, when treated with dilute acid. They turn acidified K2Cr2O7 from orange to green because of reduction of chromium ion(in dichromate solution) to +3 oxidation state.

Sulfites produce SO₂ gas, which smells of burning sulfur, when treated with dilute acid. They turn acidified K₂Cr₂O₇ from orange to green because of reduction of chromium ion(in dichromate solution) to +3 oxidation state.