Sum of $3 x^{2} - 2 x + 6$ and $6 x + 2 x^{2} + 4$ is .

5 x^{2} + 8 x + 10

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5 x^{2} + 4 x + 10

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5 x^{2} - 4 x + 10

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3 x^{2} + 4 x + 10

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Solution

The correct option is B $5 x^{2} + 4 x + 10$
Given: $(3 x^{2} - 2 x + 6) + (2 x^{2} + 6 x + 4)$
Grouping the like terms together,
$= (3 x^{2} + 2 x^{2}) + (- 2 x + 6 x) + (6 + 4)$
$= 5 x^{2} + 4 x + 10$

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Similar questions

2 x^{2} + 6 x + 3 = 0, - 3 x^{2} - x - 4 = 0, 1 + 2 x - 3 x^{2} = 0.

Subtract: 2 x^{2} + 6 - 4 x from 3 x^{2} - 6 x + 8.

2 x^{2} + 6 - 4 x

3 x^{2} - 6 x + 8

Question 6 (b)

From the sum of $4 + 3 x a n d 5 - 4 x + 2 x^{2}$ , subtract the sum of $3 x^{2} - 5 x a n d - x^{2} + 2 x + 5$ .

The sum of two binomials is $5 x^{2} - 6 x$ . If one of the binomial is $3 x^{2} - 2 x$ . Find the other.

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