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Byju's Answer
Standard XII
Mathematics
Arithmetic Progression
Sum of all th...
Question
Sum of all the integers between
100
and
1000
which are divisible by
7
is:
A
70336
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B
70400
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C
78029
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D
none of the above
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Solution
The correct option is
A
70336
S
=
105
+
112
+
.
.
.
.
.994
and
105
+
(
n
−
1
)
7
=
994
⇒
105
+
7
n
−
7
=
994
⇒
n
=
128
s
=
n
2
(
a
+
l
)
=
128
2
(
105
+
994
)
=
70336
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