Suppose $2$ kg of sugar contains $9106$ crystals. How many sugar crystals are there in (i) $5$ kg of sugar? (ii) $1.2$ kg of sugar?

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Solution

(i) No. of crystals in $5$ kg of sugar $= (\frac{9106}{2}) \times 5 = 22765$ crystals

(ii) No. of crystals in $1.2$ kg of sugar $= (\frac{9106}{2}) \times 1.2 = 5463.6$ crystals

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Question 07.2 .
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(i) 5 kg of sugar?

(ii) 1.2 kg of sugar? [2 MARKS]

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