Suppose that a box is accelerating at a rate of 2 $\frac{m}{s^{2}}$ . If the net force is tripled and the mass is doubled, then what is the new acceleration of the box? (in $\frac{m}{s^{2}}$ )

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Solution

The original value of 2 $\frac{m}{s^{2}}$ must be multiplied by 3 (since a and F are directly proportional) and divided by 2 (since a and m are inversely proportional)

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Suppose that a box is accelerating at a rate of 2 m/ $s^{2}$ If the net force is tripled and the mass is doubled, then what is the new acceleration of the box?

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Suppose that a box is accelerating at a rate of 2 ms2. If the net force is tripled and the mass is doubled, then what is the new acceleration of the box? (in ms2) ___

The original value of 2 ms2 must be multiplied by 3 (since a and F are directly proportional) and divided by 2 (since a and m are inversely proportional)

Suppose that a box is accelerating at a rate of 2 $\frac{m}{s^{2}}$ . If the net force is tripled and the mass is doubled, then what is the new acceleration of the box? (in $\frac{m}{s^{2}}$ )

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The original value of 2 $\frac{m}{s^{2}}$ must be multiplied by 3 (since a and F are directly proportional) and divided by 2 (since a and m are inversely proportional)