Tan x - tan x - -3 - tan x - 2-3 - 3-tan 3x -

The correct option is D 1 tan x + tan[x+π3]+tan[x+2π3]=3 tan x+tan x+√(3)1 √(3)tan x+tan x √(3)1+√(3)tan x=3 =3 ⇒tan(1 3tan^2x)+(tan x+√(3) ...

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Sign of Trigonometric Ratios in Different Quadrants

tan x + tan x...

Question

$tan x + tan (x + \frac{π}{3}) + tan (x + \frac{2 π}{3}) = 3 \Rightarrow tan 3 x =$

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t a n x + t a n (x + \frac{π}{3}) + t a n (x + \frac{2 π}{3}) = 3,

\frac{3 t a n x - t a n^{3} x}{1 - 3 t a n^{2} x} = 1

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(x + \frac{π}{3}) + tan (x + \frac{2 π}{3}) = 3 ⟹ tan 3 x = . . . . . .

If $t a n x + t a n (x + \frac{π}{3}) + t a n (x + \frac{2 π}{3}) = 3,$ prove that $\frac{3 t a n x - t a n^{3} x}{1 - 3 t a n^{2} x = 1.}$

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tan x + tan (x + \frac{π}{3}) + tan (x + \frac{2 π}{3}) = 3

lim x \to 0 \frac{[1 - tan (x / 2)] [1 - sin x]}{[1 - tan (x / 2)] {[π - 2 x]}^{3}}

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