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Standard Formulae - 1

Tanthita + se...

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Tanthita + secthita -1 divided by Tanthita - secthita +1 =1+sinthita divided by cost hota

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Q. The remainder when n is divided by 3 is 1 and the remainder when (n + 1) is divided by 2 is 1. The remainder when (n - 1) is divided by 6 is :

f (z)

when divided by

z - i

gives remainder

i - 1;

when divided by

z + i

gives remainder

i + 1

f (z)

z^{2} + 1

, the remainder is

(5^-1×3^-1)divided by 6^-1

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