Question

Question 63

Temperature of a place at 12:00 noon was $+5^{0}C$. Temperature increased by $3^{0}C$ in first hour and decreased by $1^{0}C$ in the second hour. What was the temperature at 2:00 PM?

Answer 1

Temperature at 12:00 noon = $+5^{0}C$

It is given that temperature increased by $3^{0}C$ in the first hour.

So, temperature at 1:00 PM = $+5^{0}C$ $+$ $3^{0}C$ = $8^{0}C$

Also, temperature decreased by $1^{0}C$ in second hour.

So, the temperature at 2.00 PM = $8^{0}C$- $1^{0}C$= $7^{0}C$

Hence, the temperature at 2.00 PM is $7^{0}C$.