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Question

Tertiary butyl alcohol gives tertiary butyl chloride on treatment with:

A
conc. HCl / anhydrous ZnCl2
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B
KCN
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C
NaOCl
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D
Cl2
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Solution

The correct option is B conc. HCl / anhydrous ZnCl2
Alcohols (secondary and tertiary) on reaction with conc. HCl and dry anhydrous ZnCl2 forms corresponding alkyl halide via SN1 mechanism. It also a chemical test to distinguish between primary, secondary and tertiary alcohols and is called the Lucas test.
Option A is correct.

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