  Question

$${\text{2PbS + 3O}}_{\text{2}} \to 2{\text{PbO + 2SO}}_{\text{2}}$$$${\text{3SO}}_{\text{2}} {\text{ + 2HNO}}_{\text{3}} {\text{ + 2H}}_{\text{2}} {\text{O}} \to {\text{3H}}_{\text{2}} {\text{SO}}_{\text{4}} {\text{ + 2NO}}$$According to the above sequence of reaction, how much $${\text{H}}_{\text{2}} {\text{SO}}_{\text{4}}$$ will be produced by 1146 gm of $$PbS$$?

A
270 g  B
360 g  C
400 g  D
470 g  Solution

The correct option is D 470 g$$2PbS+3O_2\longrightarrow 2PbO+2SO_2$$Moles of $$PbS=\cfrac{1146}{239}=4.8$$ $$moles$$$$1$$ $$mole$$ of $$PbS$$ gives $$1$$ $$mole$$ $$SO_2$$. So, $$4.8$$ $$mole$$ of $$PbS$$ gives $$4.8$$ $$mole$$ $$SO_2$$$$\underset{4.8 mole}{3SO_2} + 2HNO_3+2H_2O\longrightarrow 3H_2SO_4+2NO$$$$1$$ $$mole$$ of $$SO_2$$ gives $$1$$ $$mole$$ $$H_2SO_4$$So, $$4.8$$ $$mole$$ of $$SO_2$$ gives $$4.8$$ $$mole$$ $$H_2SO_4$$Mass of $$H_2SO_4=98\times 4.8=470$$ $$g$$Hence, the correct option is $$(D)$$.Chemistry

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