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Question

Factorise the expression 15a3b+35ab3.
  1. 5a(3a2b+7b3)
  2. 5ab(3a2+7b2)
  3. 5b(3b2a7a3)
  4. 3b(5b2a7a3)


Solution

The correct option is B 5ab(3a2+7b2)
Given, the expression is 15a3b + 35ab3.

On writing each term as the product of irreducible factors, we get,
15a3b = 3×5×a×a×a×b
35ab35×7×a×b×b×b

By taking out the common factors, we get, 
15a3b+35ab3=5ab(3a2+7b2)                      

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