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Question

Find the zeroes of the polynomial x22.


A

2 and 5

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B

4 and 3

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C

2 and 2

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D

5 and 2

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Solution

The correct option is C

2 and 2


To find the zeroes, equate the given polynomial to zero.

x22=0

Using the identity, a2b2=(a+b)(ab)

(x+2)(x2)=0

x+2=0 and x2=0

x=2 and x=2

Hence, the zeroes are 2,2.


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