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Question

If A=340o,then 1sinA1+sinA is equal to

A
2sin10o
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B
2sin10o
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C
2cos10o
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D
2cos10o
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Solution

The correct option is A 2sin10o
As,
sin170o+cos170o>0sin10o+cos10o>0sin170ocos170o<0sin10ocos10o<0

A=340o1sinA1+sinA=(sinA2cosA2)2(sinA2+cosA2)2=sinA2cosA2sinA2+cosA2=|sin170ocos170o||sin170o+cos170o|=sin170ocos170o+sin170o+cos170o=2sin170o=2sin10o

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