CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If  A=[2222],then An=2kA,where k=
  1. 2n1  
  2. n+1    
  3. n1    
  4. 2(n1)     


Solution

The correct option is D 2(n1)     
A=[2222]

Then  A2=[2222][2222]

=[8888]=4[2222]=4A     (i)

A3=A2A=4AA     [From (i)]
    =4A2=44A=16A=24A=22(31)A

A4=A3A=16A.A
    =16A2=64A=26A=22(41)A

An=22(n1)A
k=2(n1)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image