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Question

If 0x2(x2+a2)(x2+b2)(x2+c2)dx=π2(a+b)(b+c)(c+a)then, 0dx(x2+1)(x2+16)=
  1. π2
  2. π40
  3. π60
  4. π80


Solution

The correct option is B π40
0dx(x2+4)(x2+9)=0x2(x2+4)(x2+9)(x2+0)dxa=1,b=4,c=00dx(x2+4)(x2+9)=π2(5)(4)(1)=π40

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