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Question

If f(x)=1+x2, then ____


A
f(xy)=f(x)+f(y)
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B
f(xy)f(x)×f(y)
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C
f(xy)f(x)×f(y)
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D
f(xy)=f(x)×f(y)
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Solution

The correct option is B f(xy)f(x)×f(y)
Given, f(x)=1+x2
f(y)=1+y2 and f(xy)=1+(xy)2
f(x)×f(y)=1+x2×1+y2
=1+x2+y2+x2y2

As 1+(xy)21+x2+y2+x2y2
f(xy)f(x)×f(y)

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