If in a - ABC - - A -45- - B -60- and - C -75- - find the ratio of its sides-

∠ A=45^∘; ∠ B=60^∘, and ∠ C=75^∘ Using sine rule, a/sin A=b/sin B=c/sin C=k a/sin 45=b/sin 60=c/sin 75=k =a/1/√(2)=b/√(3)/2=c/√(3)+1/2√(2)=k a:b:c=2:√(6):(√(3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Area Using Sine Rule

If in a Δ ABC...

Question

$If in a Δ A B C, ∠ A = 45^{\circ}, ∠ B = 60^{\circ}, and ∠ C = 75^{\circ}; find the ratio of its sides.$

Open in App

Solution

$∠ A = 45^{\circ}; ∠ B = 60^{\circ}, and ∠ C = 75^{\circ} Using sine rule, \frac{a}{s i n A} = \frac{b}{s i n B} = \frac{c}{s i n C} = k \frac{a}{s i n 45} = \frac{b}{s i n 60} = \frac{c}{s i n 75} = k = \frac{\frac{a}{1}}{\sqrt{2}} = \frac{\frac{b}{\sqrt{3}}}{2} = \frac{\frac{c}{\sqrt{3} + 1}}{2 \sqrt{2}} = k a : b : c = 2 : \sqrt{6} : (\sqrt{3} + 1)$

Suggest Corrections

Similar questions

Q. If in ∆ABC, ∠A = 45°, ∠B = 60° and ∠C = 75°, find the ratio of its sides.

In a $∠ A B C,$ if $∠ A = 45^{\circ}, ∠ B = 60^{\circ}, a n d ∠ C = 75^{\circ},$ find the ratio of its sides.

Q. In

Δ A B C, ∠ A = 45^{\circ}, ∠ B = 60^{\circ}

, and

∠ C = 75^{\circ}

. Find the angles formed by joining the mid-points of the sides of the given triangle.

In $Δ A B C, ∠ A = 45^{\circ}, ∠ B = 60^{\circ}$ and $∠ C = 75^{\circ}$ . The angles of the triangle formed by joining the mid-points of the sides of this triangle are

Q. In

Δ A B C, ∠ A = 45^{\circ}, ∠ B = 60^{\circ}

and

∠ C = 75^{\circ}

. The angles of the triangle formed by joining the mid – points of the sides of this triangles are:

Join BYJU'S Learning Program

If in a ΔABC, ∠A=45∘, ∠B=60∘, and ∠C=75∘; find the ratio of its sides.

∠A=45∘; ∠B=60∘, and ∠C=75∘ Using sine rule,asin A=bsin B=csin C=kasin 45=bsin 60=csin 75=k=a1√2=b√32=c√3+12√2=ka:b:c=2:√6:(√3+1)

$If in a Δ A B C, ∠ A = 45^{\circ}, ∠ B = 60^{\circ}, and ∠ C = 75^{\circ}; find the ratio of its sides.$