If tan θ+cot θ=2, then tan2θ+cot2θ = _____.
-2
0
1
2
Given tan θ+cot θ=2
Squaring both sides we get,
(tan θ+cot θ)2=22
tan2θ+2(tan θ cot θ)+cot2θ=4
tan2 θ+2+cot2 θ=4 (∵ tan θ cot θ=1)
∴ tan2 θ+cot2 θ=2
If (tan θ + cot θ) = 5 then (tan2 θ + cot2 θ) = ?
(a) 27 (b) 25 (c) 24 (d) 23