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Question

If x, y, zR, then the value of determinant
∣ ∣ ∣(5x+5x)2(5x5x)21(6x+6x)2(6x6x)21(7x+7x)2(7x7x)21∣ ∣ ∣ is

A
10
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B
12
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C
1
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D
0
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Solution

The correct option is D 0
=∣ ∣ ∣(5x+5x)2(5x5x)21(6x+6x)2(6x6x)21(7x+7x)2(7x7x)21∣ ∣ ∣

Applying C1C1C2, we get
=∣ ∣ ∣4(5x5x)214(6x6x)214(7x7x)21∣ ∣ ∣

=4∣ ∣ ∣1(5x5x)211(6x6x)211(7x7x)21∣ ∣ ∣

=4×0=0

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