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Question

In ΔPQR,the angle bisectors of PQR and PRQ meet at O.

If QPR=80,find the measure ofQOR.

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Solution


1=2=12Q (OQ bisects PQR)
Q=22
3=4=12R (OR bisects PRQ)
R=23
In ΔPQR,80+Q+R=180
Q+R=100
22+23=100
2(2+3)=100
2+3=50
In ΔQOR,2+3+QOR=18050+QOR=180
QOR=18050=130

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