Let f(x)=3x10−7x8+5x8−21x3+3x2−7 THENlimh→0f(1−h)−f(1)h3+3h
50/3
22/3
3
53/3
limh→0f(1−h)−f(1)h3+3h=limh→0f(1−h)−f(1)−h.1h2+3=f′(1)(−13)=533Hence (d) is the correct answer