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Question

The general solution of the equation 7 cos2θ+3 sin2θ=4 is



Your Answer
A

(a) θ=2 nπ± π6,nZ

Your Answer
B

(b) θ=2 nπ± 2π3,nZ

Correct Answer
C

(c) θ= nπ± π3,nZ

Your Answer
D

(d) none of these


Solution

The correct option is C

(c) θ= nπ± π3,nZ


Given:7 cos2 θ+3 sin2 θ=47 cos2 θ+3(1 cos2 θ)=47 cos2 θ+33 cos2 θ=44 cos2 θ+3=44(1cos2 θ)=34 sin2 θ=3sin2θ=34sin θ=32sin θ=sin π3θ=nπ±π3,nZ

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