The principal value of cos - 1 - sin7-6is -

The correct option is B 5π/3 We have, cos ^ 1 ( sin( 7π #160; 6 #160; ) #160; #160; ) #160; ⇒cos ^ 1 ( cos( π #160; 2 + 7π ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Domain and Range of Basic Inverse Trigonometric Functions

The principal...

Question

$The principal value of {cos}^{- 1} (- sin \frac{7 π}{6}) is :$

\frac{5 π}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{7 π}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{π}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

∣ ∣ ∣ 1 - \frac{| sin x |}{1 + | sin x |} ∣ ∣ ∣ \geq \frac{2}{3}

x

cos 3 x + sin (2 x - \frac{7 π}{6}) = - 2

x

{(\frac{5 π}{12})}^{\circ}

- {(\frac{7 π}{12})}^{\circ}

\frac{π}{3}

\frac{5 π^{\circ}}{6}

\frac{2 π^{\circ}}{9}

\frac{7 π^{\circ}}{24}

$c o s^{- 1} (c o s \frac{7 π}{6})$ is equal to
a) $\frac{7 π}{6}$
b) $\frac{5 π}{6}$
c) $\frac{π}{3}$
d) $\frac{π}{6}$

If the product of the roots of equation 2 $x^{2}$ + ax + 4 sin a = 0 is 1, then roots will be imaginary if :

Join BYJU'S Learning Program