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Question

10 x Sin1x1x2dx=

A
0
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B
1
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C
12
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D
2
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Solution

The correct option is B 1
Put θ=Sin1x. Then dθ=11x2dx. x=0, 1θ=0,π2
10 x Sin1x1x2dx=π20 sinθ dθ=[θ(cosθ)]π20π201(cos θ)dθ=[sinθ]π20=1

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