-0-8sec-2-2x-2dx-1-41-31-2None-of-these

The correct option is A 1/41/2∫_0^π/8 sec^2 2xdx=1/4[tan 2x]^π/8_0=1/4[1]=1/4. ...

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First Fundamental Theorem of Calculus

∫_0^π/8sec^2 ...

Question

$\int_{0}^{\frac{π}{8}} \frac{s e c^{2} 2 x}{2} d x =$

\frac{1}{4}

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\frac{1}{3}

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\frac{1}{2}

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N o n e o f t h e s e

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Solution

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Similar questions

\int_{0}^{\frac{π}{8}} \frac{s e c^{2} 2 x}{2} d x =

\int_{0}^{π / 2} \frac{d x}{1 + {tan}^{5} x} = \frac{π}{4}

\int_{0}^{a} f (x) d x = \int_{0}^{a} f (a + x) d x = \int_{0}^{π / 2} \frac{d x}{1 + {tan}^{3} x} = \int_{0}^{π / 2} \frac{d_{X}}{1 + {cot}^{3} x} = \frac{π}{4}

\int_{0}^{\frac{π}{4}} (2 {sec}^{2} x + x^{3} + 2) d x

\int_{0}^{π} \sqrt{\frac{1 + C o s 2 x}{2}} d x =

\int_{0}^{π / 2} \frac{d x}{1 + tan x}

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