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Question

x20x+sin x1+cos xdx=   [Roorkee 1978]



A
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B
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C
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Solution

The correct option is B
x20x+sin x1+cos xdx=x20x+sin x2 cos2 x2dx
=12x20 x sec2 x2dx+x20 tanx2dx
=x tanx2π20=π2 tan π4=π2

Mathematics

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