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Question

0eaxcos bxdx=
  1. None of these
  2. aa2+b2
  3. ba2+b2
  4. ba2b2


Solution

The correct option is B aa2+b2
Let I=0eax cos bx dx
=[(1acosbx.eax)0+0basinbxeaxdx]
=1ab2a2I(1+b2a2)I=1a
I=aa2+b2

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