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Question
∫1−1x|x|dx= [MP PET 1990; Pb. CET 2004]
∫1−1x|x|dx= [MP PET 1990; Pb. CET 2004]
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Solution
Let f(x)=x|x|. Then f(−x)=−x|−x|=−x|x|=−f(x)
Therefore ∫1−1x|x|dx=0
(By the property of definite integral).
Let f(x)=x|x|. Then f(−x)=−x|−x|=−x|x|=−f(x)
Therefore ∫1−1x|x|dx=0
(By the property of definite integral).
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